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In the electrochemical reaction 2Fe^(3...

In the electrochemical reaction
`2Fe^(3+)+Zn to Zn^(2+) + 2Fe^(2+)`
Increasing the concentration of `Fe^(2+)`

A

increases cell emf

B

increases the current flow

C

decreases the cell emf

D

alters the pH of the solution.

Text Solution

Verified by Experts

The correct Answer is:
C
Nernst equation ,
`E_("cell")=E_("cell")^(@)-(2.303RT)/(2F)"log"([Zn^(2+)][Fe^(2+)]^(2))/([Fe^(3+)]^(2))`
Increasing `[Fe^(2+)]` will decrease the `E_("cell")`.
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