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At equilibrium , number of atoms disinte...

At equilibrium , number of atoms disintegrating at two different stages are in the ratio of 1: 10 . It half life of first stages is 15 minutes , half life of second stage would be

A

150 min

B

15 min

C

1.5 min

D

30 min

Text Solution

Verified by Experts

The correct Answer is:
A

`(N_(A))/(N_(B))=((t_(1//2))A)/((t_(1//2))B)`
`N_(A)//N_(B)=1//10, (t_(1//2))_(A)=15` min
`(t_(1//2))_(B)=15xx10=150` min
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