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The State of hybridisation of phosphorus...

The State of hybridisation of phosphorus (Z=15) in phosphate ion `(PO_(4)^(3-))` is the same as

A

I in `ICI_(4)^(-)`

B

S in `SO_(3)`

C

N in `NO_(3)^(-)`

D

S in `SO_(3)^(2-)`

Text Solution

Verified by Experts

The correct Answer is:
D
Hybridisation of `P=sp^(3) ("in" PO_(4)^(3-))`
`H=(1)/(2)[5+3]=4`
Similarly , in `SO_(3)^(-2), H=(1)/(2)[6+2]=4`
i.e., S is `sp^(3)` hybridised
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