" The grabh of "y=6" is a lire "

After solving the linear equations -6x+5y=2 and -5x+6y=9 . The value of y will be :

[" The solution of equation "],[log((dy)/(dx))=9x-6y+6;" given that "],[y(0)=1" is "],[[" (1) "4e^(6y)=3e^(9x+6)+e^(6)," ( ) "],[" (2) "3e^(6y)=4e^(9x+6)-e^(6)," 3e "6y=2e^(9x+6)+e^(6)],[" (4) "2e^(6y)=3e^(9x+6)-e^(6)]]

Let (dy)/(dx)=(6)/(x+y) where y(0)=0 then the value of y when x+y=6 is

Find the area of the figure enclosed by the curve 5x^2+6x y+2y^2+7x+6y+6=0.

Find the area of the figure enclosed by the curve 5x^2+6x y+2y^2+7x+6y+6=0.

Find the area of the figure enclosed by the curve 5x^2+6x y+2y^2+7x+6y+6=0.

If the average of the list {5, 6, 6, 8, 9, x, y} is 6, then what is the value of x + y ?