" i) "(dy)/(dx)=(1+y^(2))/(1+x^(2))" [Way "19" TS "

(dy)/(dx)=(y^(2)+y+1)/(x^(2)+x+1)

(dy)/(dx)=(y^(2)-y+1)/(x^(2)-x+1)

(dy)/(dx)=2((y+2)^(2))/((x+y-1)^(2))

Solve the following differential equations. (i) (dy)/(dx) =(1+y^(2))/(1+x^(2)) (ii) (dy)/(dx) = (sqrt(1-y^(2)))/(sqrt(1-x^(2))) (iii) (dy)/(dx) = 2y tan hx (iv) sqrt(1+x^(2))dx + sqrt(1+y^(2))dy = 0 (v) (dy)/(dy) = e^(x-y)+x^(2)e^(-y)

(y-x(dy)/(dx))=3(1-x^(2)(dy)/(dx))

The solution of (dy)/(dx) = (1+y^(2))(1+x^(2))^(-1) is

Find (dy)/(dx) ,if y=(x^(2)+1)(x^(2)-1)

(dy)/(dx)=(x+y+1)/(2x+2y+3)

(dy)/(dx)=(x+y+1)/(2x+2y+3)

(dy)/(dx) + (1)/(x) * y = x ^(2)