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" 1.Prove that the point on the parabola...

" 1.Prove that the point on the parabola "y^(2)=4ax,(a>0)" nearest to the focus is its vertex."

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Prove that the point on the parabola y^(2) = 4ax (a gt0) nearest to the focus is its vertex.

Prove that the point on the parabola y^(2) = 4ax (a gt0) nearest to the focus is its vertex.

Prove that the point on the parabola y^(2) = 4a ( a gt 0 nearest to the focus is its vertex.

The focus of the parabola y^2= 4ax is :

The point on y^(2)=4ax nearest to the focus has to abscissa equal to

The point on y^(2)=4ax nearest to the focus has to abscissa equal to

The point on y^(2) = 4ax nearest to the focus has its abscissa equal to