Find the equation of a curve passing through the point `(2, 3)`, given that the slope of the tangent to the curve at any point (x, y) is `(2x)/(y^2)`.

Explanation

Given slope is ,

`=>(dy)/(dx)​=(2x)/(y^2)`​

`=>dyy^2=2xdx`


Integrating both sides,

`=>∫y^2dy=∫2xdx`

`=>(y^3)/3​=x^2+C`


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