Find the equation of the curve passing through the point (1, 1) whose differential equation is `x dy =(2x^2+1)dx(x!=0)`.

Explanation

To find the equation of the curve passing through the point (1, 1) whose differential equation is given by \( x \, dy = (2x^2 + 1) \, dx \), we can follow these steps:

### Step 1: Rearrange the Differential Equation
We start with the given differential equation:
\[ x \, dy = (2x^2 + 1) \, dx \]
We can rearrange this to isolate \( dy \):
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