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Evaluate : tan^(-1)1+tan^(-1)2+tan^(-1)3...

Evaluate : `tan^(-1)1+tan^(-1)2+tan^(-1)3`.

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The value of tan^(-1)1+tan^(-1)2+tan^(-1)3 is

tan^(-1)2-tan^(-1)1=tan^(-1)(1/3)

tan^(-1)2-tan^(-1)1=tan^(-1)(1/3)

tan^(-1)2-tan^(-1)1=tan^(-1)(1/3)

Prove that : tan^(-1) 1 + tan^(-1) 2 + tan^(-1) 3= pi = 2(tan^(-1) 1 + tan^(-1)((1)/(2)) + tan^(-1)( (1)/(3)))

tan^(-1)3-tan^(-1)2=tan^(-1)(1/7)

tan^(-1)3-tan^(-1)2=tan^(-1)(1/7)

The numerical value of tan^(-1) 1+ tan^(-1) (1/2) + tan^(-1) (1/3) =_______.

tan^(-1)1+tan^(-1)1/3=?