Equation of axis of parabola `y^(2)+6y-2x+5=0` is

The axis of the parabola y^(2)+2x=0 is

Focus of parabola y^(2)-x+4y+5=0 is

Focus of parabola y^(2)-x+4y+5=0 is

The axis of the parabola y^(2)+4x+4y-3=0 is

Axis of the parabola x ^(2) -4x-3y+10=0 is

Write the distance between the vertex and focus of the parabola y^(2)+6y+2x+5=0

Find the focus, vertex, equation of the directrix and the axis of the parabola x = y^(2) - 2y + 3 .

The equation of a normal to the parabola y=x^(2)-6x+6 which is perpendicular to the line joining the origin to the vertex of the parabola is