[" In Fig.9.23,"E" is any point on median AD of a "],[Delta ABC" .Show that ar "(ABE)=ar(ACE)" ."]

E is any point on median AD of a triangle ABC . Show that ar (ABE) = ar (ACE).

In the figure 11.23, E is any point on median AD of a Delta ABC. Show that ar (ABE) = ar (ACE).

In Fig.9.23, E is any point on median AD of a DeltaA B C . Show that a r\ (A B E)\ =\ a r\ (A C E)dot

In the Given figure, E is any point on median AD of a triangle ABC Show that ar (ABE) = ar (ACE)

In the adjoining figure,E is a point on the median AD of a Delta ABC. Show that ar (Delta ABE)=(Delta ACE)

In the figure, E is any point on median AD of a triangleABC . Show that ar( triangleABE )= ar( triangleACE ).

E is any point on median AD of DeltaABC . If ar (DeltaABE) = 10 cm^2 then ar (DeltaACE) is :

E is any point on median AD of DeltaABC . If ar (DeltaABE) = 10 cm^2 then ar (DeltaACE) is :

E is any point on median AD of /_ABC .If ar(Delta ABE)=10cm^(2) then ar(Delta ACE) is

In Fig.9.16,P is a point in the interior of a parallelogram ABCD.Show that (i) ar(APB)+ar(PCD)=(1)/(2)ar(ABCD)(ii)ar(APD)+ar(PBC)=ar(APB)+ar(PCD)