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[" 8."(sin18^(@))/(cos72^(@))=cdots cdot...

[" 8."(sin18^(@))/(cos72^(@))=cdots cdots],[[" (a) "0," (b) "1," (c) "2]]

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(sin 18^@)/( cos 72 ^@) = ?

Evaluate: (sin18^(@))/(cos72^(@))

Prove that (sin18^(@))/(cos72^(@))=1

Evaluate : (sin 18^(@))/(cos72^(@))

Evalute: (b) (sin18^(@))/(cos72^(@))

Evaluate : (sin 18^(@))/(cos 72^(@))

sin18^(@)-cos72^(@) is equal of :

Evaluate : (sin18^@)/(cos72^@) .

Evaluate : (sin 18^@)/(cos 72^@)