x^(2)-xy+7y^(2)

Subtract : 5x^(2)-3xy -7y^(2) from 3x^(2)-xy-2y^(2)

The equation x^(2)-7xy-y^(2)=0 represents

The equation x^(2)-7xy-y^(2)=0 represents

If 7x^(2)-kxy-7y^(2)=0 represents the joint equation of the bisectors of the angles between the lines given by 2x^(2)-7xy+4y^(2)=0 , then k=

If the equation 7x^(2)-kxy-7y^(2)=0 represents the bisectors of angles between the lines 2x^(2)-7xy+4y^(2)=0 then: k=

Subtract the second polynomial from the first : 3x^(2)y-7xy^(2) +5xy, 2xy-x^(2)y +7xy^(2)

Subtract the second polynomial from the first : 3x^(2)y-7xy^(2) +5xy, 2xy-x^(2)y +7xy^(2)

If x^(4)+x^(2)y^(2)+y^(4)=133 and x^(2)-xy+y^(2)=7, then what is the value of xy ?

3x^(2)-20xy-7y^(2)