" If "x=a sec theta,y=b tan theta" then "(dy)/(dx)=

If x = a sec theta , y =b tan theta , then (d^2y)/(dx^2) at theta = pi/6 is :

If x =a cos theta , y =b sin theta then (dy)/(dx) =

If x=a sec theta , y=b tan theta find (d^2 y )/( dx^2) at x = (pi )/( 6)

If x = sin theta, y = tan theta then find (dy)/(dx)

1. If x = at ^(2) , y = 2 at then (dy)/(dx) at t =1 is A 2 If x =cos theta, y = sin theta then (dy)/(dx) at theta = (pi)/(4) is B 3 If x =1 - cos theta, y = sin theta , then (dy )/(dx) at theta = (pi)/(6) is C 4 If x = log sin theta, y = tan theta then (dy)/(dx) at theta = (pi)/(4) is D. The ascending order of A,B,C,D is

If x=a sec^2 theta,y=a tan^2 theta , then (d^2x)/(dy^2)=

x=a cos theta,y=b sin theta then find dy/dx

If x =a cot theta , y=b cosec theta ,then (dy)/(dx)=

If x=a sec theta and y=b tan theta then b^(2)x^(2)-a^(2)y^(2) =_____.

If x=a sec theta,y=b tan theta, prove that (d^(2)y)/(dx^(2))=-(b^(4))/(a^(2)y^(3))