Home
Class 11
CHEMISTRY
A decapeptide (Mol. Wt. 769) on complete...

A decapeptide (Mol. Wt. 769) on complete hydrolysis gives glycine (Mol. Wt. 75), alanine and phenylalanine.
Glycine contributes `47.0 %` to the total weight of the hydrolysed products. The number of glycine units. Present in the decapeptide is.

A

4

B

5

C

6

D

7

Text Solution

Verified by Experts

The correct Answer is:
C

Mol . Wt . Of decapeptide =796 u
Number of water molecules used for hydrolysis of decapeptide =9
i.e., Decapeptide +`9H_(2)O to ` glycine +alanine +Phenylalanine
Total weight of amino acids obtained after addition of 9 molecules of water
=796+9x 18 =958 u
Now total weight of glycine in the hydrolysed product `=(958xx47)/100 =450.26 u`
But mol. wt. of glycine =75 u
`:.` No of glycine units in decapaptide `450.26/75 =6`
Promotional Banner

Similar Questions

Explore conceptually related problems

A decapeptide (Molecular weight 796) on complete hydrolysis gives glycine (Molecular weight 75), alanine and phenylanine. Glycine contributes 47.0 % to the total weight of the hydrolysed products. The number of glycine units present in the decapeptide is

An octapeptide (Mol.wt = 516 g ) on complete hydrolysis given glycine and alanine (Mol. Mass = 89 g ). Alanine contributes 41.59 % to total weight of hydrolysed product. How many number of alanine unit present in octapeptide.

A polypeptide (Mol. wt = 360 ) formed by glycine (Mol. wt = 75 ) amino acid. How many glycine units are used to form it.

Each mole of substance A (Molar mass =720 ) required 10 moles of water for complete hydrolysis and gives B,C and D as the hydrolysed product in a molar ratio of 2:3:2. if molecular mass of B is 40 and it contributes 40% of total mass of hydrolysed product then moles of C obtained will be

The equivalent weight of a species if acts as oxidant or reductant should be derived by : Eq. weight of oxidant or reductant = ("Mol. wt. of oxidant or reductant")/{("Number of electrons lost or gained by one"),("moleculae of oxidant or reductant"):} During chemical reactions, equal equivalents of one species react with same number of equivalents of other species giving same number of equivalent of products. However this is not true for reactants if they react in terms of moles. Also Molarity can be converted to normality by multiplying the molarity with valence factor or 'n' factor. Equivalent weight of Fe_(2)O_(3) in terms of its mol. weight in the change Fe_(3)O_(4)rarrFe_(2)O_(3) is

The equivalent weight of a species if acts as oxidant or reductant should be derived by : Eq. weight of oxidant or reductant = ("Mol. wt. of oxidant or reductant")/{("Number of electrons lost or gained by one"),("moleculae of oxidant or reductant"):} During chemical reactions, equal equivalents of one species react with same number of equivalents of other species giving same number of equivalent of products. However this is not true for reactants if they react in terms of moles. Also Molarity can be converted to normality by multiplying the molarity with valence factor or 'n' factor. The equivalent weight of an element is 13.16 . It forms an acidic oxide which with KOH forms a salt isomorphous with K_(2)SO_(4) . The atomic weight of element is: