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If NaOH is added to an aqueous solution ...

If NaOH is added to an aqueous solution of `Zn^(+2)` ions white precipitate appears and on adding excess NaOH, the precipitate dissolves. In solution zinc is in the

A

Cationic part

B

Anionic part

C

Both in cationic and anionic parts

D

There is no zinc left in the solution.

Text Solution

Verified by Experts

The correct Answer is:
B
`Zn^(2+)+2NaOHrarr2Na^(2+)+Zn(OH)_(2)`
`Zn(OH)_(2)+2NaOHrarrNa_(2)ZnO_(2)+2H_(2)O`
`Na_(2)ZnO_(2)` ionises as 2 `Na^(+)` and `[ZnO_(2)]^(2-)`
`therefore` Zinc occurs as anion.
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