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When sodium reacts with excess of oxygen...

When sodium reacts with excess of oxygen, oxidation number of oxygen changes from

A

`0-1`

B

`0-2`

C

`-1` to `-2`

D

`+1` to `-1`.

Text Solution

Verified by Experts

The correct Answer is:
A
`2Na+O_(2)rarrNa_(2)O_(2)`
Oxidation number of oxygen is 0 in `O_(2)` and `-1` in `Na_(2)O_(2)`.
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