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In electrolysis of NaCl when Pt electrod...

In electrolysis of `NaCl` when `Pt` electrode is taken `H_(2)` is liberated at cathode while `Hg` cathode it forms sodium amalgam because

A

Hg is more inert than Pt

B

More voltage is required to reduce `H^(+)` at Hg than at Pt

C

Na is dissolved in Hg while it does not dissolve in Pt

D

Concentration of `H^(+)` ions is larger when Pt electrode is taken.

Text Solution

Verified by Experts

The correct Answer is:
B
More voltage is required to reduce `H^(+)` at Hg-cathode than at Pt-cathode.
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