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A ball A moving with momentum 2hati + 4h...

A ball A moving with momentum `2hati + 4hatj` collides with identical ball B moving with momentum `6hatj` . After collision momentum of ball B is `10 hatj` . Which of the following statement is correct?

A

After collision momentum of A is `4hati`

B

After collision momentum of A is parallel to momentum of B

C

After collision momentum of A is `2 hati`

D

If `vecP_A and vecP_B` are momenta of balls A and B, then `Delta(|vecP_A | + |vecP_B|) = 0`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the momentum of the two balls before and after the collision. 1. **Identify the initial momentum of both balls:** - Ball A has an initial momentum of \( \vec{p_A} = 2\hat{i} + 4\hat{j} \). - Ball B has an initial momentum of \( \vec{p_B} = 0\hat{i} + 6\hat{j} \). 2. **Calculate the total initial momentum:** - The total initial momentum \( \vec{p_{initial}} \) is the vector sum of the momenta of both balls: \[ \vec{p_{initial}} = \vec{p_A} + \vec{p_B} = (2\hat{i} + 4\hat{j}) + (0\hat{i} + 6\hat{j}) = 2\hat{i} + 10\hat{j} \] 3. **Identify the final momentum of ball B:** - After the collision, the momentum of ball B is given as \( \vec{p_B'} = 0\hat{i} + 10\hat{j} \). 4. **Let’s denote the final momentum of ball A as \( \vec{p_A'} \).** - We know that momentum is conserved, so the total final momentum \( \vec{p_{final}} \) must equal the total initial momentum: \[ \vec{p_{final}} = \vec{p_A'} + \vec{p_B'} = \vec{p_A'} + (0\hat{i} + 10\hat{j}) \] 5. **Set up the equation for momentum conservation:** \[ \vec{p_{initial}} = \vec{p_{final}} \implies 2\hat{i} + 10\hat{j} = \vec{p_A'} + (0\hat{i} + 10\hat{j}) \] 6. **Solve for \( \vec{p_A'} \):** - By equating the components, we find: - In the \( \hat{i} \) direction: \[ 2 = p_{A_x}' \quad \text{(where \( p_{A_x}' \) is the \( \hat{i} \) component of \( \vec{p_A'} \))} \] - In the \( \hat{j} \) direction: \[ 10 = p_{A_y}' + 10 \implies p_{A_y}' = 0 \] 7. **Thus, the final momentum of ball A is:** \[ \vec{p_A'} = 2\hat{i} + 0\hat{j} = 2\hat{i} \] 8. **Conclusion:** - The correct statement is that after the collision, the momentum of ball A is \( 2\hat{i} \).

To solve the problem, we need to analyze the momentum of the two balls before and after the collision. 1. **Identify the initial momentum of both balls:** - Ball A has an initial momentum of \( \vec{p_A} = 2\hat{i} + 4\hat{j} \). - Ball B has an initial momentum of \( \vec{p_B} = 0\hat{i} + 6\hat{j} \). 2. **Calculate the total initial momentum:** - The total initial momentum \( \vec{p_{initial}} \) is the vector sum of the momenta of both balls: ...
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