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A ball A of mass M collides elastically ...

A ball A of mass M collides elastically with a similar ball B at rest as shown in figure. Initially velocity of ball A is u m/s. After collision,

A

Speed of ball B is u `sin theta`

B

Velocity of ball A is `u sin^2 theta hati + u sin theta cos theta hatj`

C

Speed of ball A is `u cos theta`

D

`Velocity of ball B is `u cos theta sin theta hati + u cos^2 theta hatj`

Text Solution

Verified by Experts

The correct Answer is:
B

`implies barV_A = u sin theta(sin theta hati + cos theta hatj) = u sin^2 theta hati + u sin theta cos theta hatj`
`barV_(B) = u cos theta(cos theta hati - sin theta) = u cos^2 theta hati - u sin theta cos theta hatj`
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