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A force exerts an impulse I on a particl...

A force exerts an impulse I on a particle changing its speed from u to 2u. The applied force and the initial velocity are oppositely directed along the same line. The work done by the force is

A

`3/2 Iu`

B

`1/2 Iu`

C

`Iu`

D

`2 Iu`

Text Solution

Verified by Experts

The correct Answer is:
B
Impulse = change in momentum.
`implies I = m(2u) - m (-u) = 3 m u implies m = I/(3u)` and work done = change in KE
`= 1/2m (2u)^(2) - 1/2 m u^2 = 3/2 ((I)/(3u)) u^2 = (Iu)/2`.
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