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A sphere is moving with velocity vector ...

A sphere is moving with velocity vector `2hati+2hatj` immediately before it hits a vertical wall. The wall is parallel to `hatj` and the coefficient of restitution of the sphere and the wall is `e=1/2`. Find the velocity of the sphere after it hits the wall?

A

`hati - hatj`

B

`-hati + 2hatj`

C

`-hati - hatj`

D

`2hati - hatj`

Text Solution

Verified by Experts

The correct Answer is:
B
Along the wall (i.e. along y-axis) component of velocity remains same & perpendicular to wall it becomes - e times. `implies` Final velocity `= -hati + 2 hatj`.
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