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A forceF=(3thati + 5hatj)N acts on a bod...

A force`F=(3thati + 5hatj)N` acts on a body due to which its displacement varies as `S=(2t^(2)hati-5hatj)m`. Work done by these force in `2 s` is .

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The correct Answer is:
24
`v = (dS)/(dt) = (4t) hati " "P = F.v = 12t^2 :. " " w = int_(0)^(2) Pdt = int_(0)^(2) (12) t^2 dt = 24 J`.
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