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A constant power P is applied to a parti...

A constant power `P` is applied to a particle of mass `m`. The distance traveled by the particle when its velocity increases from `v_(1)` to `v_(2)` is (neglect friction):

A

`(3P)/m (v_2^2 - v_1^2)`

B

`(m)/(3P) (v_2 - v_1)`

C

`m/(3P) (v_2^3 - v_1^3)`

D

`m/(3P) (v_2^2 - v_1^2)`

Text Solution

Verified by Experts

The correct Answer is:
C
`P = Fv = mav implies a = P/(mv) implies m int_(v_1)^(v_2) v^2 dv = P int_(0)^(s) ds implies S = m/(3P) (v_2^2 - v_1^2)`.
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