The system shown is released from rest. Mass of ball is m kg and that of wedge is M kg respectively. When ball reaches at highest point on other side of the wedge, velocity of ball and wedge is (initially wedge is kept at rest against a wall and there is no friction anywhere) :

Options

A. `(Msqrt(2 gR))/(m + M)`
B. `(Msqrt(2 gR))/(M)`
C. `M/m sqrt(2 gR)`
D. `(msqrt(2gR))/(m + M)`

Answer

D

Explanation

Let h : height gain by ball above the bottom

`implies` Wedge will not move till the ball reaches at bottom with velocity `sqrt(2gR)`
`implies m sqrt(2gR) = (m + M) V implies (msqrt(2 gR))/(m + M)`