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A bomb of mass 9 kg explodes into 2 piec...

A bomb of mass 9 kg explodes into 2 pieces of mass 3 kg and 6 kg. The velocity of mass 3 kg is 1.6 m/s, the K.E. of mass 6 kg is:

A

3.84 J

B

9.6 J

C

1 . 92 J

D

2. 92 J

Text Solution

Verified by Experts

The correct Answer is:
C
The bomb initially was at rest therefore
Initial momentum of bomb = 0
Final momentum of system = `m_1v_1 + m_2v_2`
As there is no external force
`:.m_1v_1 + m_2v_2 = 0 implies 3 xx 1.6 + 6 xx v_2 = 0`
Velocity of 6 kg mass, `v_2 = 0.8 m//s ("numerically")`
Its kinetic energy `=1/2 m_2v_2^2 = 1/2 xx 6 xx (0.8)^2 = 1.92J`
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