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which a U^(238) nucleus original at rest...

which a `U^(238)` nucleus original at rest , decay by emitting an alpha particle having a speed `u` , the recoil speed of the residual nucleus is

A

`- 4 v// 2 3 4`

B

`v//4`

C

`-4 v // 2 3 8`

D

`4 v // 2 3 8`

Text Solution

Verified by Experts

The correct Answer is:
A
Initially `.^(238)U` nucleus was at rest and after decay its parts move in opposite directions.
According to conservation of momentum,
`4v + 234 V = 238 xx 0 implies V = - (4v)/(234)`
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