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A force acts on a 2 kg object so that it...

A force acts on a 2 kg object so that its position is given as a function of time as `x=3t^(2)+5.` What is the work done by this force in first 5 seconds ?

A

950 J

B

900 J

C

875 J

D

850 J

Text Solution

Verified by Experts

The correct Answer is:
B
`x = 3t^2 + 5 " "v = 6t, " "W = DeltaKE = 1/2 m(V_2^2 - V_1^2) = 1(39=0^2 - 0^2) = 900 J`.
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