A piece of wood of mass 0.03 kg is dropped from the top of a building 100 m high. At the same time, a bullet of mass 0.02 kg is fired vertically upward with a velocity of 100 m/s from the ground the bullet gets embedded in the wooded piece after striking. find the height to which the combination rises above the building before it starts falling take `g=10m//s^(2)`

Options

A. 40 m
B. 30 m
C. 10 m
D. 20 m

Answer

A

Explanation

`X_(cm) = (0.03 xx 100)/(0.05) = 60 cm`
`V_(cm, i) = (0.02 xx 100)/(0.05)`
`= 40 m//s`
h above `P = (40^2)/(2 xx 10) = (1600)/(20) = 80`
Height above top of building = 80 - 40m.