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A liquid flows through two capillary tub...

A liquid flows through two capillary tubes A and B connected in series. The length and radius of B are twice that of A. What is the ratio of the pressure difference across A to that across B ?

A

8

B

4

C

2

D

1

Text Solution

Verified by Experts

The correct Answer is:
A
` Q _ 1 = (pi P_1 r _ 1 ^4 )/( 8 eta l _ 1 ) and Q _2 = (pi P _2 r _ 2 ^4 )/(8 eta l _2 ) ` Since the tubes are connected in series, ` Q _1 = Q _ 2 `
or ` (piP _ 1 r _ 1^4 ) /(8 eta l _ 1 ) = (pi P_2 r _ 2 ^4 )/(8 eta l _ 2 ) ` or ` (P_1 ) /(P_2) = ((l_1)/(l_2)) xx((r_2)/(r_1))^4 = ((1)/(2)) xx 2 ^4 = 8 `
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