The cylindrical tube of a spray pump has a cross-section of `8 cm^2`, one end of which has `40` fine holes each of area `10^-8 m^2`. If the liquid flows inside the tube with a speed of `0.15 m min^-1`, the speed with which the liquid is ejected through the holes is.

Answer

5

Explanation

According to equation of continuity, av = constant
` therefore ` For tube , ` (8 xx 10 ^(-4)) xx ((0.15)/(60)) = a _ 1 v _ 1` , For holes ` (40 xx 10 ^(-8)) xx v = a _ 2 v _ 2 `
` therefore a _ 1 v _ 2 = a_ 1 v _ 1 therefore 40 xx 10 ^(-8) xx v = (8 xx 10 ^(-4) xx 0.15) /(60) rArr v = (8 xx 10 ^(-4) xx 0.15)/(40 xx10 ^(-8) xx v ) = ( 8 xx 10 ^(-4) xx 0.15) /(60 ) rArr v = (8 xx 10 ^(-4) xx 0.15)/(40 xx 10 ^(-8) xx 60 ) = 5 m s ^(-1) `