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Water from a tap emerges vertically down...

Water from a tap emerges vertically downwards with an initial spped of `1.0ms^-1`. The cross-sectional area of the tap is `10^-4m^2`. Assume that the pressure is constant throughout the stream of water, and that the flow is steady. The cross-sectional area of the stream 0.15 m below the tap is

A

` 5 xx 10 ^(-4) m ^ 2 `

B

` 1 xx 10 ^(-5 ) m ^ 2 `

C

`2 xx 10 ^(-5 ) m^2 `

D

` 5 xx 10 ^(-5 ) m ^ 2 `

Text Solution

Verified by Experts

The correct Answer is:
D

`P_(0)+rhogh+(1)/(2)rhov_(1)^(2)=P_(0)+(1)/(2)rhov_(2)^(2)`
`RightarrowV_(2)^(2)=V_(1)^(2)+2gh`
`V_(2)=2m//s`
`A_(1)V_(1)=A_(2)V_(2)RightarrowA_(2)=(10^(-4))/(2)=5xx10^(-5)m^(2)`
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