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A soap bubble,blown by a mechanical pump...

A soap bubble,blown by a mechanical pump at the mouth of a tube, increases in volume, with the time, at a constant rate. The graph that correctly depicts the time dependence of pressure inside the bubble is given by :

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Text Solution

Verified by Experts

`DeltaP=(4s)/(R)" ""Given"(dV)/(dt)`=constant = C(say) where V is the volume
Since `V=(4)/(3)piR^(3)to(d((4)/(3)piR^(3)))/(dt)=Cto(4)/(3)piR^(3)=ct+V_(0)`
`toR=(Ct+V_(0))^(1//3)xx(3)/(4pi)" "toRinftyt^(1//3)" "Delta"P"infty(4S)/(t^(1//3))`
Hence, bonus
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