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A homogeneous solid cylinder of length L...

A homogeneous solid cylinder of length L(LltH/2), cross-sectional area A/5 is immersed such that it floats with its axis vertical at the liquid-liquid interface with length L/4 in the denser liquid as shown in the figure. The lower density liquid is open to atmosphere having pressure `P_0`. Then density D of solid is given by

A

` (5)/(4) d `

B

` (4)/(5) d `

C

` 4d `

D

` (d)/(3) `

Text Solution

Verified by Experts

The correct Answer is:
A

Weight of cylinder = Upthrust due to upper liquid + upthrust due to lower liquid
`rArrD((A)/(5))xxLxxg=d((A)/(5))[(3)/(4)L]g+2d[(A)/(5)][(L)/(4)]xxg" "therefore" "D=5d//4`
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