A 2 g bullet moving with a velocity of 200 m/s is brought to a sudden stoppage by an obstacle. The total heat produced goes to the bullet. If the specific heat of the bullet is `0.03 cal//g^@C`, the rise in its temperature will be

Options

A. `158.0^(@)C`
B. `15.80^(@)C`
C. `1.58^(@)C`
D. `0.1580^(@)C`

Answer

A

Explanation

`(mV^(2))/(2J)=msDeltaT,DeltaT=(V^(2))/(2sJ)square158.0^(@)C`