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The variation of length of two metal rod...


The variation of length of two metal rods A and B with change in temperature is shown in Fig. the coefficient of linear expansion `alpha_A` for the metal A and the temperature T will be? ( alpha_(A)=3x10^(-6)/ C )

A

`alpha_(A)=3xx10^(-6)//^(@)C,500^(@)C`

B

`alpha_(A)=3xx10^(-6)//^(@)C,222.22^(@)C`

C

`alpha_(A)=27xx10^(-6)//^(@)C,500^(@)C`

D

`alpha_(A)=27xx10^(-6)//^(@)C,222 22^(@)C`

Text Solution

Verified by Experts

The correct Answer is:
D

For rod B : `1004=1002(1+(9xx10^(-6))T)rArrT=(2000)/(9)K`
For rod A: `1006=1000(1+alpha_(A)T)rArralpha_(A)=27xx10^(-6)//^(@)C`
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