A heat flux of 4000 J/s is to be passed through a copper rod of length 10 cm and area of cross section `100cm^2`. The thermal conductivity of copper is `400W//m//^(@)C` The two ends of this rod must be kept at a temperature difference of

Options

A. `1^(@)C`
B. `10^(@)C`
C. `100^(@)C`
D. `1000^(@)C`

Answer

C

Explanation

`(dQ)/(dt)=4000=((400)ADeltaT)/(l)or,10=(ADeltaT)/(l),or,DeltaT=(10l)/(A)=(10xx0.1)/(100xx10^(4))=100^(@)C`