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Two sheets of thickness d and 3d, are to...

Two sheets of thickness d and 3d, are touching each other. The temperature just outside the thinner sheet is `T_1` and on the side of the thicker sheet is `T_3`. The interface temperature is `T_2. T_1, T_2 and T_3` are in arithmetic progression. The ratio of thermal conductivity of thinner sheet to thicker sheet is .

A

`1 : 3`

B

`3 : 1`

C

`2 : 3`

D

`3 : 9`

Text Solution

Verified by Experts

The correct Answer is:
A
`therefore(T_(1)-T_(2))/((d//K_(1)A))=(T_(2)-T_(3))/((3d//K_(2)A))`
`therefore(K_(1))/(K_(2))=((T_(2)-T_(3))/(T_(1)-T_(2))).(1)/(3)`
But `T_(1):T_(2)andT_(3)` are in AP
`thereforeT_(2)-T_(3)=T_(1)-T_(2)`
`therefore(K_(1))/(K_(2))=(1)/(3)`
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