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The breaking stress for a substance is 1...

The breaking stress for a substance is `10^(6)N//m^(2)`. What length of the wire of this substance should be suspended vertically so that the wire breaks under its own weight? (Given: density of material of the wire `=4xx10^(3)kg//m^(3)` and `g=10 ms^(-2))`

A

10 m

B

15 m

C

25 m

D

34 m

Text Solution

Verified by Experts

The correct Answer is:
C
Maximum tension is at the top. So T = mg
so, `(T)/(A)=rholg`
`l=("m ax stress")/(rhog)=(10^(6))/(4xx10^(3)xx10)=25m`
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