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A cube of side 40 cm has its upper face ...

A cube of side 40 cm has its upper face displaced by 0.1 mm by a tangential force of 8 Kn. The shearing modulus of cube is :-

A

`2xx10^(9)Nm^(-2)`

B

`4xx10^(9)Nm^(-2)`

C

`8xx10^(9)Nm^(-2)`

D

`16xx10^(9)Nm^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
A
Shearing modulus of cube, `eta=(FL)/(Al)`
`=(8xx10^(3)xx40xx10^(-3))/((40xx10^(-3))^(2)xx(0.1xx10^(-3)))=2xx10^(9)Nm^(-2)`
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