A bob of mass 10 kg is attached to wire 0.3 m long. Its breaking stress is `4.8 xx 10^(7) N//m^(2)`. The area of cross section of the wire is `10^(-6) m^(2)`. The maximum angular velocity with which it can be rotated in a horizontal circle

Answer

4

Explanation

Breaking strength = tension `=mromega^(2)`
`4.8xx10^(7)xx10^(-6)=10xx0.3omega^(2),omega=4rad//sec`.