A clock with a metallic pendulum gains 5 s each day at a temperature of `15^@C` and loses 10 s each day at a temperature of `30^@C`. Find the coefficient of thermal expansion of the pendulum metal.

Answer

2

Explanation

Loss or gain per day `=dT=(1)/(2)alphadtxx86400`
Since , T =86400 s for each day
At `15^(@)C,5=(1)/(2)alpha(t-15)(86400)," At "30^(@)C,10=(1)/(2)alpha(30-t)xx86400rArr(30-t)/(t-15)=2rArrt=20^(@)Cs`