Two identical beakers A and B contain equal volumes of two different liquids at `60^@C` each and left to cool down. Liquid in A has density of `8xx10^(2)kg//m^3` and specific heat of `2000 J kg ^(-1)K^(-1)` while liquid in B has density of `10^(3)kgm^(-3)` and specific heat of `4000J kg ^(-1)K^-1` . Which of the following best describes their temperature versus time graph schematically ? (assume the emissivity of both the beakers to be the same)

Options

A.
B.
C.
D.

Answer

B

Explanation

`Mass_(A)=Vxx8xx10^(2)" "mass_(B)=Vxx10^(3)`
`thereforemass_(B)gtmass_(A)`
`|(msd theta)/(dt)|=k|(theta-theta_(0))|rArr|(d theta)/(dt)|theta-theta_(0)|`
`m_(A)S_(A)=Vxx8xx10^(2)xx2000 " " mB^(S)B=Vxx10^(3)xx4000`
`thereforem_(B)S_(B)gtm_(A)S_(A)therefore` slope of A will greater in magnitude at t = 0