Two spherical bodies A (radius 6cm) and B (radius 18cm) are at temperature `T_(1)` and `T_(2)` respectively The maximum intensity in the emission spectrum of A is at `500 nm` and in that of `B` is at `1500nm` considering them to be black bodies, what will be the ratio of the rate of total energy radiated by A to that of `B` . ?

Answer

9

Explanation

`lambda_(m)T="constant"lambda_(A)T_(A)=lambda_(A)T_(A)=lambda_(B)T_(B)`
Now rate of total energy radiated `propAT^(4)rArr(E_(A))/(E_(B))=((T_(A))/(T_(B)))^(4)xx((R_(A))/(R_(B)))^(2)=(3)^(4)xx((6)/(18))^(2)=9`