300 grams of water at `25^@ C` is added to 100 grams of ice at `0^@ C.` The final temperature of the mixture is _____ `^@C`

Answer

0

Explanation

Heat liberated when 300 g water at 25°C goes to water at `0^(@)C:Q=msDeltatheta=(300)(1)(25)=7500cal`
From this much heat can melt mass of ice given by `m=(Q)/(L)=(7500)/(80)=93.75g`
i.e. whole ice will not melt.
Hence, the mixture will be at 0°C.
Mass of water in mixture `=300+93.75,=393.75g` and
Mass of ice in mixture