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What is the area of the plates of a 2 fa...

What is the area of the plates of a 2 farad parallel plate air capacitor, given that the separation between the plates is 0.5 cm?

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Capacitance of parallel plate capacitor `C=(epsi_(0)A)/(d)` , Area `A=(Cd)/(epsi_(0))=(2xx(0.5xx10^(-2)))/(8.85xx10^(-12))=1.13xx10^(9)m^(2)`
this is too large. That is why ordinary capacitors are in the range of `muF` or even less, however, in electrolytic capacitors the separation (d) is very small, so they have capacitances of the order of 0.1F.
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