An uncharged capacitor of capacitance C is connected with a battery of EMF V and a resistance R. The switch is closed at `t=0`. The time instant at which the current in the circuit is `(V)/(4R)` is t=

Options

A. 2RC
B. 3RC
C. `2RClog_(e)2`
D. `3RClog_(e)2`

Answer

C

Explanation

Current in the circuit, `i=(V)/(R) e^(-(t)/(RC)),` Therefore, current is `(V)/(4R)` at t=2RC`log_(e)2`