If the capacitor shown in the circuit is charged to 5V and left in the circuit, in 12s the charge on the capacitor will become:

Options

A. `(10)/(e)C`
B. `(e)/(10)C`
C. `(10)/(e^(2))C`
D. `(e^(2))/(10)C`

Answer

A

Explanation

`q=q_(0)e^(-t//RC)=10e^(-12//12)=(10)/(e)C`