In the given circuit diagram, both capacitors are initially uncharged. The capacitance `C_(1)=2muF and C_(2)=4muF`, emf of battery A and B are 2V and 4V respectively.

Answer

(A-R;B-P;C-5;D-Q)

Explanation

`(A)toR,(B)toP,(C)toS,(D)toQ`
(A) Work done by battery `A=2((1)/(2)C_(1)V_(1)^(2))=2xx2^(2)=8J`
(B) Work done by battery `B=2[(1)/(2)CV_(2)^(2)]=2[(1)/(2)xx(4xx2)/(4+2)xx4^(2)]=(64)/(3)J`
(C) `q_(2)=CV=((4xx2)/(4+2))xx4=(16)/(3)`
(D) `q_(1)=C_(1)V_(1)=2xx2=4`.