A parallel pate capacitor of capacitance ‘C’ has charge on its plates initially as shown in the figure. Now at the switch ‘S’ is closed. Select the correct alternative (s) for this circuit diagram.

Options

A. In steady state the charges on the outer surfaces of plates ‘A’ and ‘B’ will be same in magnitude and sign
B. In steady state the charges on the outer surfaces of plates ‘A’ and ‘B’ will be same in magnitude and opposite in sign
C. In steady state the charges on the inner surfaces of the plates ‘A’ and ‘B’ will be same in magnitude and opposite in sign
D. The work done by the cell by the time steady state is reached is `(5epsilon^(2)C)/(2)`

Answer

A, C, D

Explanation

Suppose charge flown through the battery is then charge distribution will be as:
The electric field in the region between A and B is
`(Q-2epsiC)/(2Aepsi_(0))-((epsiC-Q))/(2Aepsi_(0))=(2Q-3epsiC)/(2Aepsi_(0))`.